Capacitor Impedance Formula:
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Definition: This calculator determines the impedance of a capacitor at a given frequency.
Purpose: It helps electronics engineers and students analyze AC circuits containing capacitors.
The calculator uses the formula:
Where:
Explanation: The calculator computes the magnitude of the complex impedance, showing how much a capacitor resists AC current at a specific frequency.
Details: Understanding capacitor impedance is crucial for designing filters, timing circuits, and AC coupling applications.
Tips: Enter the frequency in Hz and capacitance in farads (default 1μF = 0.000001F). All values must be > 0.
Q1: Why does impedance decrease with frequency?
A: Capacitors conduct better at higher frequencies, so their opposition to current (impedance) decreases.
Q2: What's the phase relationship in capacitor impedance?
A: Current leads voltage by 90° in an ideal capacitor.
Q3: How do I convert between Hz and rad/s?
A: Multiply Hz by \( 2\pi \) to get rad/s (angular frequency).
Q4: What's a typical capacitor value?
A: Common values range from pF (10⁻¹²F) to mF (10⁻³F).
Q5: Does this work for DC circuits?
A: At DC (0Hz), capacitor impedance is theoretically infinite (open circuit).