1. What is Parallel Wire Inductance?

Definition: This calculator computes the inductance per unit length of two parallel wires carrying current in opposite directions.

Purpose: It helps electrical engineers and designers determine the inductance of parallel wire configurations used in transmission lines and other applications.

2. How Does the Calculator Work?

The calculator uses the formula:

Where:

• \( L \) — Inductance per unit length (Henries/meter)
• \( \mu_0 \) — Permeability of free space (4π×10⁻⁷ H/m)
• \( d \) — Separation between wire centers (meters)
• \( r \) — Wire radius (meters)

Explanation: The formula calculates the self-inductance of two parallel wires where current flows in opposite directions.

3. Importance of Parallel Wire Inductance

Details: Understanding parallel wire inductance is crucial for designing transmission lines, minimizing signal distortion, and calculating impedance in electrical systems.

4. Using the Calculator

Tips: Enter the center-to-center distance between wires and the wire radius (both in meters). The wire separation must be greater than the wire radius.

5. Frequently Asked Questions (FAQ)

Q1: What is the permeability of free space (μ₀)?
A: It's a physical constant equal to 4π×10⁻⁷ H/m that represents magnetic permeability in a vacuum.

Q2: Does this formula account for skin effect?
A: No, this is the DC inductance formula. At high frequencies, skin effect would need to be considered.

Q3: What if my wires have insulation?
A: The formula still applies as long as the insulation doesn't significantly affect the magnetic fields (non-magnetic insulation).

Q4: How does wire material affect the result?
A: For non-magnetic materials like copper, the result is accurate. For magnetic materials, additional factors would need consideration.

Q5: What's the practical application of this calculation?
A: It's used in designing twin-lead transmission lines, calculating impedance, and analyzing signal propagation in parallel conductors.